3*[n+2*(3n+2)]=138

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Solution for 3*[n+2*(3n+2)]=138 equation: 


Simplifying
3[n + 2(3n + 2)] = 138

Reorder the terms:
3[n + 2(2 + 3n)] = 138
3[n + (2 * 2 + 3n * 2)] = 138
3[n + (4 + 6n)] = 138

Reorder the terms:
3[4 + n + 6n] = 138

Combine like terms: n + 6n = 7n
3[4 + 7n] = 138
[4 * 3 + 7n * 3] = 138
[12 + 21n] = 138

Solving
12 + 21n = 138

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 21n = 138 + -12

Combine like terms: 12 + -12 = 0
0 + 21n = 138 + -12
21n = 138 + -12

Combine like terms: 138 + -12 = 126
21n = 126

Divide each side by '21'.
n = 6

Simplifying
n = 6

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